Work out the equation of the line which passes through the point (-1, 2) and is parallel to the line y=x+4

The equation of line for point can be determine by general equation of line.

The equation of line for point is .

Given:

The line is parallel to line .

The line passes through the point .

Write the general equation for line.

-------------------------- (1)

Here, is slope and is y-intercept.

Write the given line equation.

-----------------------------(2)

On comparing equation (1) and (2) we get,

As per the definition of line, parallel line has equal slope.

Substitute , and for the given point in equation (1).

Write the equation of line from the above value.

Thus, the equation of line for point is .

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The equation of the line which passes through the point (-1, 2) and is parallel to the line y = x + 4 is y = x + 3

Gtiven that line passes through the point (-1, 2) and parallel to line y = x + 4

We have to find the equation of line

The equation of line in slope intercept form is given as:

y = mx + c   eqn 1

where "m" is the slope of line and "c" is the y - intercept

Let us first find the slope of line

Given equation of line is y = x + 4

On comparing the given equation of line y = x + 4 with general slope intercept form y = mx + c,

we get slope of line "m" = 1

We know that slopes of parallel lines are equal

So the slope of line parallel to line having equation y = x + 4 is also 1

Now we have to find the equation of line having slope "m" = 1 and passes through point (-1, 2)

Substitute m = 1 and (x, y) = (-1, 2) in eqn 1

2 = 1(-1) + c

2 = -1 + c

c = 3

Thus the required equation of line is:

Substitute c = 3 and m = 1 in eqn 1

y = 1x + 3

y = x + 3

Thus the required equation of line is found out

what does x eaqual

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