Write an equation of a circle with center {-1,2} passing through the point {2,4}

The equation of circle passing through points  (2, 4) and center (-1 , 2) is (x  + 1 )² + (y - 2)² = 13

Step-by-step explanation:

Given as :

The circle having center = (-1 , 2)

The circle passes through point = (2, 4)

Now, Standard equation of circle with center and passing through points is

(x - h)² + (y -k)² = r²

where h and k are the center of circle and r is the radius of circle

Now the center as (h,k) = (-1 , 2)

And passing through points (x,y) = (2, 4)

Now, satisfying the center and points on standard circle equation

I.e (x - h)² + (y -k)² = r²

Or, (2 - (-1) )²+ (4 -2)² = r²

or, 3² + 2² = r²

or,  r² = 9 + 4

Or ,  r² = 13

∴  r =

Now circle equation

(x - (-1) )² + (y -2)² = ()²

or, (x  + 1 )² + (y - 2)² = 13

So, equation of circle is (x  + 1 )² + (y - 2)² = 13

Hence The equation of circle passing through points  (2, 4) and center        (-1 , 2) is (x  + 1 )² + (y - 2)² = 13   Answer

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step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.