One minute after take off, an airplane altitude was 4,000 feet. three minutes later , it was 20,000 feet what was the planes average altitude change , in feet per minute, during those three minutes

The average altitude change of plane with time is 8,000 feet per min .

Step-by-step explanation:

Given as :

The initial height of plane after 1 min take off = 4,000 feet

The final height of plane after 3 min later = 20,000 feet

Let The rate of change of altitude in feet per min = s feet per min

Now, According to question

The change in altitude = final altitude - initial altitude

Or, D = 20,000 feet - 4,000 feet

I.e Distance change = 16,000 feet

The change in time = final time - initial time

Or T = 3 min - 1 min

I.e Time change = 2 min

Speed =

So, s = feet per min

∴    s = 8,000 feet per min

So, Rate of change of altitude with respect to time = s = 8,000 feet per min

Hence The average altitude change of plane with time is 8,000 feet per min . Answer

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680