What point divides the directed line segment ab ⁢ into a 3: 4 ratio? (4, 3) (7, 3) (9, 3) (12, 3) segment a b in the coordinate plane with endpoint a at 1 comma 3 and endpoint b at 15 comma 3.

Therefore, the coordinates of point P(x ,y) are P ( 7 , 3 ) which divides the directed line segment AB into 3 : 4.Step-by-step explanation:

Given:

point A( x₁ , y₁) ≡ ( 0 ,-5)

point B( x₂ , y₂) ≡ (2 , 0)

Let point p( x , y ) divide Line AB in the ratio 3 : 4 i.e m : n

To Find:

P ( x, y ) = ?

Solution:

if point P( x , y) divide segment AB internally in the ratio m : n then the X coordinate and the Y coordinate is given by section formula:

On substituting the above given values in section formula we get

Therefore, the coordinates of point P(x ,y) are P ( 7 , 3 ) which divides the directed line segment AB into 3 : 4.

alot

step-by-step explanation:

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answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: