If h(x) = ln(x + p), where p > 0, what is the effect of increasing p on
(a) the y-intercept?
- it increases.
- it decreases.
- it does not change.
(b) the x-intercept?
- it moves to the right.
- it does not change.
- it moves to the left.

Step-by-step explanation:

a) y intercept means y value when x = 0

    We have h(x) = ln(x + p)

                     y = ln(x + p)

    Substituting

                     y =   ln(0 + p) = ln p

                     As p increases y intercept also increases.

     y intercept increases.

b) x intercept means x value when y = 0

    We have h(x) = ln(x + p)

                     y = ln(x + p)

    Substituting

                     0 =   ln(x + p)

                      x + p = e⁰

                      x = 1 - p

                     As p increases x intercept decreases.

     x intercept moves to the left.

im guessing (23,14). hope this : )