Rectangle abcd is dilated to create rectangle a'b'c'd' . the width of rectangle abcd is 8 feet. the width of rectangle a'b'c'd' is 6 feet. the area of rectangle abcd is 96 square feet.

what is the area of rectangle a'b'c'd' ? i need

54 square feet

Step-by-step explanation:

The width of the rectangle ABCD is 8 feet and the area of the same rectangle is 96 square feet.

Hence, the length of the rectangle is (96 ÷ 8) = 12 feet.

Now, if the rectangle ABCD is dilated to rectangle A'B'C'D', then the length and the width of the new rectangle will be changed in the same ratio.

So,  {Where AB is the length and BC is the width}

⇒

⇒ A'B' = 9 feet

Therefore, the area of the dilated rectangle A'B'C'D' will be A'B' × B'C' = 9 × 6 = 54 square feet. (Answer)

109 is the nearest whole number/final answer! : )

54

step-by-step explanation: