Narcisse and aristide have numbers of arcade tokens in the ratio 7 : 3, respectively. narcisse gives aristide some of his tokens, and the new ratio is 6 : 5. what is the least number of tokens that narcisse could have given to aristide? a. 9b. 17c. 21d. 27e. 53

Narcisse could have given 17

Step-by-step explanation:

Given that Narcisse and Aristide have numbers of arcade tokens in the ratio 7 : 3

Let Narcisse have 7x and Aristide 3x respectively

If d tokens are given from Narcisse to Aristide, new belongings

7x-d, 3x+d

Ratio is 6:5

i.e. So x should be a multiple of 11

least number of x =11

Verify:

Narcisse and Aristide have intially 77 and 33.

Narcisse gave 17 to Aristide

New are 60 and 50 making ratio 6:5

So answer is 17

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.