1- which is an equation in point-slope form for the line that passes through the points (−1,4) and (3,−4) ?

y−3=−2(x+4)

y−4=2(x+3)

y+4=−2(x−3)

y+4=2(x−3)
2- which equation is a point slope form equation for line ab ?

y+6=−2(x−1)

y+1=−2(x−6)

y+5=−2(x−2)

y+2=−2(x−5)

The first one is y + 4 = -2(x-3)

Step-by-step explanation:

Sorry its a bit lengthy, but I found this by putting the coordinates into the point slope formula, (y1-y2)/x1-x2)

y1 = 4

y2 = -4

x1 = -1

x2 = 3

I plugged in the numbers and set up my problem to look like this:

(4) - (-4)

(-1) - (3)

I simplified it to -8/4, to -2/1. -2/1 is the slope that goes through the coordinates.

Next, I solved the option equations to see which one matched my slope, which left me with two options that matched:

y-3=-2(x+4)

and

y+4=-2(x-3)

I simplified then into their slope forms and got:

y=-2x-5

and

y=-2x+2

So, now I had to find the y-intercept. For this, I just substituted x for 0, since our y-intercept occurs where there is no x-intercept.

y=-2(0)-5

Then solve for y.

y=-2(0)-5

y=0-5

y=-5

So, our answer is y-3=2(x+4)

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day