Given rectangle abcd with vertices a(1, 4), b(3, 6), c(6, 3), and d(4, 1), what is the
perimeter of abcd? leave your answer in simplified radical form.

  10√2

Step-by-step explanation:

A(1, 4), B(3, 6), C(6, 3), D(4, 1)

The distance formula tells you the distance d between two points (x1, y1) and (x2, y2) is given by ...

  d = √((x2-x1)² +(y2-y1)²

Then the side lengths are ...

  AB = √(2² +2²) = √8 = 2√2

  BC = √(3² +(-3)²) = √18 = 3√2

The perimeter is twice the sum of these sides, so is ...

  P = 2(2√2 +3√2) = 10√2 . . . the perimeter of the rectangle

answer: 25 is the correct answer

step-by-step explanation:

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse