One positive integer is 3 greater than 4 times another positive integer. if the product of the two integers is 76, then what is the sum of the two integers?
14
23
21
19

The sum of the two integers is 23

Step-by-step explanation:

Let one integer be x and the other integer be y

Then according to the statement "One positive integer is 3 greater than 4 times another positive integer.."

x be the integer that is One positive integer is 3 greater than 4 times another positive integer.

Then

x= 3+4y----------------------------------(1)

Product of the two integer is 76, this can  written as

substituting the values of x from eq(1)

Solving the quadratic equation equation we get

here

a = 4

b= 3

c = -76

susbtituting the above values in the formula

y= 4                                                           y =  −4.75

Since in the  question it is given that it is a positive integer

so  y = 4

substituting y=4 in eq (1) we get,

x= 3+4(4)

x= 3+16

x= 19

The sum of the two integers

=> x + y

=> 19+4

=>23

f(x) = y

f(-3) = -5

step-by-step explanation: