The area of a rectangular wall of a barn is 126 square feet. it’s length is 4 feet longer than twice it’s width. find the length and the width of the wall of the barn.

The width is 7 feet and length is 18 feet

Step-by-step explanation:

Let length of rectangle be "l" and width of rectangle be "w"

The area of a rectangle is length * width

Area is given as 126, so we can write:

Also, given length is 4 feet longer than TWICE width, so we can write:

l = 4 + 2w

We replace first equation with this equation and simplify to get:

We can do middle term factorization and find the value(s) of w:

Width CANNOT be negative, so we take w = 7

Now, finding l:

l = 4 + 2w

l = 4 + 2(7)

l = 4 + 14

l = 18

The width is 7 feet and length is 18 feet

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

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step-by-step explanation: