Which inequality has no solution?

6(x+2)> x-3

3+4x< 2(1+2x)

-2(x+6)< x-20

x-9 < 3 (x-3)

we will proceed to solve all cases to determine the solution of the problem

case A)

Eliminate the parenthesis of the left side

Group terms that contain the same variable, and move the constants to the opposite side of the inequality

Combine like terms

The solution is the interval--------> (-3,∞)

All real numbers greater than

therefore

The inequality A has solution

case B)

Eliminate the parenthesis of the right side

Group terms that contain the same variable, and move the constants to the opposite side of the inequality

Combine like terms

---------> is not true

therefore

The inequality B has no solution

case C)

Eliminate the parenthesis of the left side

Group terms that contain the same variable, and move the constants to the opposite side of the inequality

Combine like terms

Multiply by both sides

The solution is the interval--------> (8/3,∞)

All real numbers greater than

therefore

The inequality C has solution

case D)

Eliminate the parenthesis of the right side

Group terms that contain the same variable, and move the constants to the opposite side of the inequality

Combine like terms

Multiply by both sides

The solution is the interval--------> (0,∞)

All real numbers greater than

therefore

The inequality D has solution

therefore

the answer is

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: