Solve the matrix equation 2 upper x minus upper a equals upper b2x−a=b for x. let upper a equals left bracket start 2 by 3 matrix 1st row 1st column 5 2nd column 9 3rd column negative 7 2nd row 1st column 4 2nd column negative 3 3rd column 1 endmatrix right bracketa= 5 9 −7 4 −3 1 and upper b equals left bracket start 2 by 3 matrix 1st row 1st column negative 2 2nd column 1 3rd column 0 2nd row 1st column 4 2nd column 6 3rd column 3 endmatrix right bracketb= −2 1 0 4 6 3 .

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

answer: 7270

step-by-step explanation:

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step-by-step explanation: