Three fair, standard six-faced dice of different colors are rolled. in how many ways can the dice be rolled such that the sum of the numbers rolled is 10?

The dice be rolled in 27 ways such that the sum of the numbers rolled is 10.

Step-by-step explanation:

We can get a sum of 10 in the following ordered pairs,

(1,3,6)

(2,3,5)

(2,2,6)

(2,4,4)

(3,1,6)

(3,2,5)

(3,3,4)

(4,1,5)

(5,2,3)

These pairs can be arranged each in 3 ways.

Therefore, 9× 3

= 27.

The dice be rolled in 27 ways such that the sum of the numbers rolled is 10.

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it

no solution

step-by-step explanation:

there is not enough information in the problem to solve.