We have two boxes, each containing three balls: one black and two white in box 1; two black and one white in box 2. we choose one of the boxes at random, where the probability of choosing box 1 is equal to some given p, and then draw a ball.

1. describe the map rule for deciding the identity of the box based on whether the drawn ball is black or white.

2. assuming that p = 1 2 , find the probability of an incorrect decision and compare it with the probability of error if no ball had been drawn.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

the answer will be b x² +x-1

step-by-step explanation: