Some steps to construct an angle mnt congruent to angle pqr are listed below. step 3 is not listed: step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b. step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x. step 3: step 4: join points n and y using a straightedge.

step 3: place the tip of the compass at point x and strike the arc at point y

Step-by-step explanation:

congruent triangles are triangles that have equal shape and size. They are the same in every way. this is the reason why they are called CONGRUENT

we have been asked to construct an angle MNT congruent to angle PQR. this means we are to construct angle that is the same as that at PQR.

with a ruler and a compass we can easily make a replica of the angle at PQR.

following the steps given in the question including step 3 that i have just added, the angle MNT will be the same as the angle PQR

the answer is a

Step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2