What is the slope of a line perpendicular to a line whose equation is -4x - 2y + 18 =0 ?

Slope of a line perpendicular to a line whose equation is -4x - 2y + 18 = 0 is  

Given that the line equation is -4x - 2y + 18 = 0

We have to find the slope of line perpendicular to the above line equation

Let us first find the slope of given line

The slope intercept form of a line is given as:

y = mx + c

where "m" is the slope of line and "c" is the y - intercept

Given equation of line is:

-4x - 2y + 18 = 0

Let us rearrange the above equation into slope intercept form

2y = -4x + 18

y = -2x + 9

Comparing y = -2x + 9 with general slope intercept form y = mx + c, we get,

m = -2

Thus the slope of give line equation is -2

Now we have to find the slope of line which is perpendicular to given line having equation -4x - 2y + 18 = 0 and slope -2

Since the lines are perpendicular, product of slopes of both lines is equal to -1

Slope of line perpendicular to given line x slope of given line = -1

Slope of line perpendicular to given line x -2 = -1

Slope of line perpendicular to given line =

Thus slope of a line perpendicular to a line whose equation is -4x - 2y + 18 =0 is  

d.) 48 units

step-by-step explanation:

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