Find the inverse of the given matrix, if it exists. aequals=left bracket start 3 by 3 matrix 1st row 1st column 1 2nd column 0 3rd column negative 2 2nd row 1st column 4 2nd column 1 3rd column 3 3rd row 1st column negative 4 2nd column 2 3rd column 3 endmatrix right bracket 1 0 −2 4 1 3 −4 2 3

Step-by-step explanation:

We want to find the inverse of

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

As can be seen, we have obtained the identity matrix to the left. So, we are done.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3