‼️could somebody asap the graph is in the picture ‼️

the equation v=-32t+256 and the graph below describe the velocity v in feet per second of a ball t seconds after is is shot into the air what is the balls velocity after seven seconds

only enter the numeric value do not include units the answer will only need to be an approximation from the graph

The velocity after time t=7s. is 32 feet/s

Step-by-step explanation:

Given equation is v=(-32)t+256.

Where, v is velocity in feet/sec and t is time in seconds.

The figure show that graph of equation.

To find velocity after time t=7s.

Step 1 : Draw a graph of equation with time on x-axis and velocity of y-axis.

Step 2: Draw a line t=7and extent until it intersects with the equation of line.

Step 3: From point of intersection, draw a line parallel to x-axis and let it intersect the y-axis.

Wherever the line intersect with y-axis is answer for velocity after time t=7s.

From the figure,

The velocity after time t=7s. is 32 feet/s

Verification,

v=(-32)t+256.

When t=7s

v=(-32)(7)+256.

v=32feet/s

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)