Positive angles located in the fourth quadrant may be described

1. 0≤ф≤90
2. 180≤ф≤270
3. 90≤ф≤180
4. 270≤ф≤360

Positive angles located in the fourth quadrant may be described as 270≤Ф≤360 .

The option is

4. 270≤Ф≤360

Step-by-step explanation:

When the terminal arm of an angle starts from the x-axis in the anticlockwise direction then the angles are always positive angles.

For Example.

Quadrant I    - 0 to 90°

Quadrant II   - 90° to 180°

Quadrant III  - 180° to 270°

Quadrant IV - 270° to 360° ( 4. 270≤Ф≤360  )

Hence,Positive angles located in the fourth quadrant may be described as 270≤Ф≤360 .

When the terminal arm of an angle starts from the x-axis in the clockwise direction than the angles are negative angles.

Quadrant IV  -          0° to -90°

Quadrant III   -      - 90° to -180°

Quadrant II    -      -180° to -270°

Quadrant I     -      -270° to -360°

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

two data sets with the same median will not have the same varaibility

step-by-step explanation: