6.(x-4)^2/36-(y-2)^2/9=1
length of transverse axis:
length of conjugate axis:

7. y^2+6y-2x+13=0
length of focal chord:

can someone , i'll give extra points and mark as brainliest.

answer:

ellipse with vertical major axis (x−h)2b2+(y−k)2a2=1

hyperbola with horizontal transverse axis (x−h)2a2−(y−k)2b2=1

hyperbola with vertical transverse axis (y−k)2a2−(x−h)2b2=1

parabola with horizontal axis (y−k)2=4p(x−h) , p≠0

step-by-step explanation:

(x − h)2 = 4p(y − k), p ≠ 0 vertical axis (y − k)2 = 4p(x − h), p ≠ 0 horizontal axis 15–24 (x − h)2 a2 + (y − k)2 b2 = 1 horizontal major axis (x−h)2b2 + (y−k)2a2 = 1 658). y = k ± b a(x − h) horizontal transverse axis y = k ± a b(x − h) vertical

10cm

step-by-step explanation:

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hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )