The length of a rectangle is four times its width. if the perimeter is at most 106 centimeters, what is the greatest possible value for the width?

which inequality models this problem?

a.) 2w+ 2 • (46) < 106

b.) 2w+ 2 • (46) > 106

c.) 2w+ 2. (46) < 106

d.) 2w+ 2 · (46) > 106

Part a) The inequality that models this problem is

Part b) The greatest possible value for the width is 10.6 centimeters

Step-by-step explanation:

Part a) Which inequality models this problem?

Let

l ----> the length of the rectangle in cm

w ---> the width of the rectangle in cm

we know that

The perimeter  of the rectangle is equal to

Remember that

The term "at most" means "less than or equal to"

so

----> inequality A

---> equation B

substitute equation B in the inequality A

 ---> inequality that model the problem

Part b) what is the greatest possible value for the width?

solve for w

Divide by 10 both sides

therefore

The greatest possible value for the width is 10.6 centimeters

step-by-step explanation:

because it just is

hi there!

the answer is: 2 and -2

step-by-step explanation:

case 1: an absolute value of positive number will still be a positive number

so absolute value of 2 is 2

case 2: an absolute value of negative number will be positive number so absolute value of -2 is 2