On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases from quadrant 2 into quadrant 1. it crosses the y-axis at (0, 1).
which function is a shrink of the exponential growth function shown on the graph?

f(x) = 2(3)x
f(x) = one-half(3)x
f(x) = 2(one-third) superscript x
f(x) = one-half (one-third) superscript x

f(x) =

Step-by-step explanation:

The given options are,

a) f(x) =

b) f(x) =

c) f(x) =

d) f(x) =

Now, among the given options only option (a) satisfies the criteria stated in the question i. e.,

     1. f(x) → 0 as x → - ∞  and

     2 f(0) = 1

so, the correct answer is,

f(x) =

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?