Iam aware that this question uses second ftc, however, i keep getting the wrong answer. any guidance is appreciated.

C. 14

Step-by-step explanation:

F(x) = ∫₀²ˣ √(t³−15) dt

Use second fundamental theorem of calculus:

F'(x) = √((2x)³−15) d/dx (2x)

F'(x) = 2 √(8x³−15)

Evaluate at x=2:

F'(2) = 2 √(8×2³−15)

F'(2) = 2 √(64−15)

F'(2) = 2 √49

F'(2) = 14