Solve
write the equation of the line passing through the points (0, -4) and (-2, 2).

write the equation of the line passing through the points (-6,1) and (-4,2).

Question 1:

y-2=-3(x+2) - In Point-Slope Form

y=-3x-4 - In Slope-Intercept Form

Question 2:

y-1=1/2(x+6) - In Point-Slope Form

y=1/2x+4 - In Slope-Intercept Form

Step-by-step explanation:

Attached is a picture of the point slope formula which we will be using to write the equations of these lines...

Question 1: Write the equation of the line passing through the points (0, -4) and (-2, 2).

1) First, we need to find the slope, or "m" of this line. Lets plug these two points into slope formula (y2-y1/x2-x1):

(2--4)/(-2-0)

2) Simplify:

6/-2

3) Solve:

m=-3

4) Now, lets plug that slope into point-slope formula along with a set of points that were given to us [I will be using (-2,2)]

y-2=-3(x+2)

5) Now, if you wish to write the equation of the line in slope intercept form, we will have to do some simple algebra. First, distribute -3 to x and 2:

y-2=-3x-6

6) Next, Add 2 to both sides: (Now it is in slope-intercept form)

y=-3x-4

Question 2: Write the equation of the line passing through the points (-6,1) and (-4,2).

1) First, we need to find the slope, or "m" of this line. Lets plug these two points into slope formula (y2-y1/x2-x1):

(2-1)/(-4--6)

2) Simplify:

m=1/2

3) Now, lets plug that slope into point-slope formula along with a set of points that were given to us [I will be using (-6,1)]

y-1=1/2(x+6)

4) Now, if you wish to write the equation of the line in slope intercept form, we will have to do some simple algebra. First, distribute 1/2 to x and 6:

y-1=1/2x+3

5) Next, add 1 to both sides: (Now it is in slope-intercept form)

y=1/2x+4

im not quite sure if this is right but i got 5.6 oisutuve

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