Find three numbers such that their sum is 12, the sum of the first, twice the second, and three times the third is 31, and the sum of the third and nine times the second is 1

3,-1,10

Step-by-step explanation:

let the numbers be x,y,z.

x+y+z=12

x+2y+3z=31

z+9y=1

z=1-9y

subtract 1st from 2nd

y+2z=19

y+2(1-9y)=19

y+2-18y=19

-17 y=17

y=-1

z=1-9(-1)=1+9=10

x-1+10=12

x=12+1-10=3

i dont know

step-by-step explanation:

160

step-by-step explanation:

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