Solve the following system of equations. 3x+4y=12
2x-3y= -9

(0,3) is the solution set for given system.

Step-by-step explanation:

Given that:

3x+4y=12   eq1

2x-3y= -9 eq2

Multiplying eq1 with 2 and eq2 with 3 we get:

6x + 8y = 24 eq1

6x - 9y = -27 eq2

Subtracting eq2 from 1 we get:

17y = 51

Dividing both sides by 17 we get:

y = 3

Putting value of 3 in eq1 we get:

3x + 4(3) = 12

3x + 12 = 12

3x = 0

Dividing both sides by 3

x = 0

So the solution set will be: (0,3)

i hope it will help you.