Auniversity dean is interested in determining the proportion of students who receive some sort of financial aid. rather than examine the records for all students, the dean randomly selects 200 students and finds that 118 of them are receiving financial aid. use a 99% confidence interval to estimate the true proportion of students on financial aid.

(0.500, 1.090)

Step-by-step explanation:

Given that a university dean is interested in determining the proportion of students who receive some sort of financial aid.

A sample of (random) 200 students taken and 118 were found out receiving financial aid.

Sample proportion p =

For margin of error we use Z critical value as this is proportion and also sample size is large.  np and nq both are greater than 5.

So margin of error = 2.58*std error = 0.090

Confidence interval

=

send it over

step-by-step explanation:

idk

step-by-step explanation:

use that smart brain