Mathematics, 07.12.2019 06:31, mandy294
Ameasuring tape drops from a roof that is 16 feet above the ground. after how many seconds does the measuring tape land on the ground? how would you write the equation?
Answers: 1
![y(t)=16-\frac{1}{2} g\,t^2[/tex with acceleration due to gravity "g" = 32ft/s^2]Step-by-step explanation:This is an object moving vertically under the action of the acceleration of gravity (32 ft/s^2), with a starting position of 16 feet, and with NO initial velocity (drops from the roof).The equation that describes the"y" position of the object as a function of time (t) will be written as:[tex]y(t) = y_0+ v_0*t-\frac{1}{2} g\,t^2](/tpl/images/0407/7799/f988c.png)
s 16 ft, there is no initial velocity, so 
, and the acceleration of gravity is 32 ft/s^2, and should be considered negative [as pointing down in the y-direction], so the equation simplifies to:
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Ameasuring tape drops from a roof that is 16 feet above the ground. after how many seconds does the...
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