Aspherical snowball is melting in such a way that it maintains its shape. the snowball is decreasing in volume at a constant rate of 8 cubic centimeters per hour. at what rate, in centimeters per hour, is the radius of the snowball decreasing at the instant when the radius is 10 centimeters?

0.006366 cm/h

Step-by-step explanation:

First we need to know that the volume of a sphere is calculated with the following formula:

V = (4/3)*pi*r^3

Where V is the volume and r is its radius.

Then, to find the rate of change, we need to derivate the equation with respect to the radius:

dV/dr = (4/3)*pi*(3r^2) = 4*pi*r^2

Then, we can write dV/dr as being (dV/dt)*(dt/dr), where dt is the change of time (variable t)

(dV/dt)*(dt/dr) = 4*pi*r^2

(dV/dt) = 4*pi*r^2*(dr/dt)

The rate of change of the volume is 8 cm3/h when the radius is 10, so using these values, we can find the rate of change of the radius (dr/dt):

8 = 4*pi*10^2*(dr/dt)

8 = 400*pi*(dr/dt)

dr/dt = 8/(400*pi)

dr/dt = 0.006366 cm/h

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)

i can't read the graph

step-by-step explanation: