What is the solution to the system of equations? 1/4x-1/2y=8, 1/2x+3/4y=-5

Option D: (8, -12) is the solution set for given system.

Step-by-step explanation:

Given that:

1/4x-1/2y=8 eq1

1/2x+3/4y=-5 eq2

Multiplying eq1 by 2 we get:

1/2x - y = 16 eq3

Now by subtracting eq3 from eq2 we get:

(1/2x+3/4y) - (1/2x - y ) = -5 -16

By simplifying:

3/4y + y = -21

By taking LCM to make denominator same:

3/4y + y*4/4 = -21

3+4 / 4y = -21

7/4y = -21

Multiplying both sides by 4/7 we get

y = -21 * 4/7

y = -12

Putting value of y in eq3

1/2x - (-12)= 16

1/2x + 12 = 16

1/2x = 16 - 12

1/2x = 4

Multiplying both sides by 2

x = 4*2

x = 8

So the solution set = (8, -12)

i hope it will help you!

answer: i realy don't get it that much can you me figer it out pleas you

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form