Identify the following for the parabola: f(x)= 2(x-3)^2-8

vertex:
opens up/down:
max or min:
x-int/zeroes:
axis of symmetry:
vertical stretch/compression:
y-intercept:
domain:
range:

Suppose that f(0) = −3 and f '(x) ≤ 8 for all values of x. how large can f(4) possibly be? solution we are given that f is differentiable (and therefore continuous) everywhere. in particular, we can apply the mean value theorem on the interval [0, 4] . there exists a number c such that

Which of the following expressions is equal to 2x^2+8

Barbara deposited $300 in the bank. if the bank pays her simple interest at the rate of 4 percent per year, how much money will she have in her account at the end of 9 months?