Will give for correct answer. : )

consider the function f(x) = x^3 + 2x^2 -3 .

(a) graph the function.
(b) what are the x- and y-intercepts of the graph?

i already know how this function looks on a graph. all i want to know is how to do it.

(a) The graph is shown below.

(b)

x-intercept = (1, 0)

y-intercept = (0, -3)

Step-by-step explanation:

Given:

The function is given as:

(a)

In order to plot the graph, we need to find some points on it. We also need to find the maximum and minimum of the function.

Let us find the maximum and minimum of the function. The maxima or minima occurs when the derivative of the function is 0.

Differentiating the function with respect to 'x', we get:

Now, equating to 0, we solve for 'x'. This gives,

Now, let us find the 'y' values for the above 'x' values.

When

When

So, the point of maxima is (-1.33, -1.8) and point of minima is (0, -3). Mark these two points on the graph.

Let us take another random point for 'x'. Let

. Mark the point (-1, -2) on the graph.

Now, let . The value of 'y' is:

. Mark the point (1, 0) on the graph.

Now, draw a smooth curve passing through all of these points with a maximum curve at (-1.33, -1.8) and minimum curve at (0, -3).

The graph is shown below.

(b)

The x-intercept is at the point when 'y' value is 0. So, the point on the graph is (1, 0).

The y-intercept is at the point when 'x' value is 0. So, the point on the graph is (0, -3).

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)