Ascreen containing two slits 0.100mm apart is 1.50m from a viewing screen. light of wavelength 633nm falls on the slits. approximately how far apart are the bright fringes on the viewing screen?

distance = 9.495 mm

Step-by-step explanation:

Given data

slits distance = 0.100 mm

viewing screen distance = 1.50 m

wavelength =  633 nm

to find out

how far apart are the bright fringes on the viewing screen

solution

we use here double slit diffraction condition that is

d sin(θ) = m λ    .......................1

here m = 0, 1 , 2 , 3   .....

and here for θ small so

sin(θ) = tan(θ) =

so x = l sin (θ)

so from equation 1

x =

and

x1 =       ...............2

x2 =     ..............3

so distance x2 - x1  will be

distance =

distance =

distance = 9.495 mm

i would say c is the best answer, hope it's right!

good luck! =)

cutie~

step-by-step explanation: