1. identify the y-intercept and the axis of symmetry for the graph of
f(x) = 10x2 + 40x + 42.
a. 42; x = 4 b. 0; x = -4 c. 42; x = -2 d. – 42; x = 2

The correct option is C). 42,x=(-2)

Point (0,42) is y-intercept of f(x)

x+2=0 is equation of axis of symmetry

Step-by-step explanation:

The given function is f(x)=

To find y-intercept:

The y-intercept is point were x=0

y=f(x)=

y=f(0)=

y=42

Therefore,Point (0,42) is y-intercept of f(x)

To find axis of symmetry of f(x):

We know that f(x) is equation of parabola

Hence, the x -coordinate of the vertex of the parabola is the equation of the axis of symmetry.

if the equation of parabola is f(x)= then, the axis of symmetry is given by x=

Therefore, for f(x)=

The axis of symmetry will be,

x=

a=10 and b=40

x=

x=-2

x+2=0 is equation of axis of symmetry

Thus,

The correct option is C). 42,x=(-2)

Note: In figure, blue curve is f(x) and black line is axis of symmetry