Xand y are independent random variables. x is normally distributed with mean 1 and variance 1. y is normally distributed with mean 3 and variance 5. what is the variance of y - 2x?

1

Step-by-step explanation:

Equation of variance:

Total Variance = sum (i=1, N) {c^2,variance^2}

= c1^2*variance1^2 + c2^2*variance2^2 +

Variance of X = 1

Variance of Y = 5

Variance of Y - 2X = (1^2)*(5) - (2^2)**(1)

= 5 - 4 = 1

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: