Two bands are marching in a parade

there are 32 people marching in the first band

there are 40 people marching in the second band

the same number of people are marching in each row in both bands

what is the greatest number of people that could be marching in each row?

i need this answer asap

8

Step-by-step explanation:

Both numbers have a GCF of 8

The GCF of 32 and 40 would be 8, it's the highest number that goes into 32 and 40

it would rotate about 180 degrees.

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !