Which graph shows the solution to the following system of linear inequalities?

−3x − 3y < −3
y ≤ −x + 1

The fourth graph will be the solution.

Step-by-step explanation:

The system of linear inequalities are  

- 3x - 3y < - 3, ⇒ x + y > 1

And y ≤ -x + 1, ⇒ x + y ≤ 1

There is no solution for those two inequalities because there are no values of x and y that can satisfy both the equations.

Now, the fourth graph will be the solution as there is no shaded region for the solution in the graph and also the line x + y = 1 is plotted as a dotted line that means the solution does not include the line also. (Answer)

goog may have it for you

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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