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a rectangular pool is surrounded by a walk 2 meters wide. the pool is 3 meters longer than its width. if the total area of the pool and walk is 188 square meters more than the area of the pool, find the dimensions of the pool.

width=20m,length=23m

Step-by-step explanation:

as shown in the figure which is attached

let width of pool =x

⇒ length of pool=x+3

width of walk =2

⇒width of outer boundary of walk=x+4 (2 on each side of pool)

   length of outer boundary of walk=x+3+4=x+7

area of pool =x×(x+3)

area of walk+pool=(x+4)×(x+7)

given

total area of the pool and walk is 188 square meters more than the area of the pool

⇒(x+4)×(x+7)=188+x×(x+3)

⇒8x=160

x=20m

dimensions of pool

widh=20m

length=20+3=23m

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6