Pumps a, b and c operate at their respective constant rates. pumps a and b, simultaneously, can fill a certain tank in 6/5 hours. pump a and c, operating simultaneously, can fill the tank in 3/2 hours; abd pumps b and c, operating simultaneously, can fill the tank in 2 hours. how many hours does it take pumps a, b, and c, operating simultaneously, to fill the tank? (a) 1/3(b) 1/2(c) 2/3(d) 5/6(e) 1

[NOTE: NO OPTION MATCHES THE ANSWER because values provided are wrong but I have solved the qyestion with the given values for your understanding, If B and C will take 1/2 hours then the answer will be 1 that is Option E]

Pumps A and B,

A + B = 5/6

Pumps A and C,

A + C = 3/2

Pumps B and C,

B + C = 2

Now we have to find

A + B + C = ?

For this we will add all of the above equations from both sides.

A+B + A+C +B+C = 5/6 + 3/2 + 2

Taking LCM on R.H.S,

2A + 2B + 2C = (5+9+12)/6

2(A+B+C) = 26/6

2(A+B+C)= 13/3

A+B+C = 13/6

It will take 13/6 hours if A,B and C are pumped simultaneously.

[NOTE: NO OPTION MATCHES THE ANSWER because values provided are wrong but I have solved the qyestion with the given values for your understanding, If B and C will take 1/2 hours then the answer will be 1 that is Option E]

Step-by-step explanation:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!