Will, sue and micah went to dinner. will paid 1/4 of the bill. micah and sue paid in the ratio of 1: 3. if sue paid $15 more than will, how much did dinner cost in total?

The dinner costed $48 in total.

Step-by-step explanation:

The amount of bill paid by Will = 1/4 of bill

Amount of bill paid by Micah and Sue  1: 3

Let us assume the common factor in the ratio  = m

So, the amount paid by Micah = 1 x (m) = m

The amount paid by Sue  = 3 x (m)  = 3 m

Also, amount paid by Sue  = $15 + Amount paid by Will

So, the amount paid by Will =  amount paid by Sue - $15   = 3 m - $15

Total Bill  = Bill amount paid by ( Will + Micah + Sue)  

               =   m + 3 m + 3 m - 15  = 7 m - 15

Now, As will paid 1/4 of total bill.

⇒

or,  m = 9

Now, the total bill = 7 m - 15  = 7(9) - 15  =  $48

Hence, the dinner costed $48 in total.

step-by-step explanation:

milk=16 large

soda=280 kids

juice box=82 regular

63 soda +63 regular

124 large total