In acute triangle $abc$ we have $\cos a \cos b = \frac{1}{3}$ and $\sin a \sin b = \frac{1}{2}.$ if the area of triangle $abc$ is 1, what is the area of the orthic triangle? (the orthic triangle has vertices at the feet of the altitudes of the triangle.)

answer: i realy don't get it that much can you me figer it out pleas you

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.

d.) 48 units

step-by-step explanation: