Arecent study in a small city stated that the average age of robbery victims was 63.5 years. a sample of 20 recent victims had a mean of 63.7 years and a standard deviation of 1.9 years. at α =0.01, is the average age higher than originally believed? make sure to write down the hypotheses, claim, critical value, test statistic, decision and conclusion

No, the average age is not higher than originally believed.

Step-by-step explanation:

Since we have given that

Sample size = 20

Mean = 63.7 years

Standard deviation = 1.9 years

So, Hypothesis:

So, the value of test statistic would be

At α = 0.01 level of significance,

critical value z = 2.58

Since 2.58>0.471

so, We will accept the null hypothesis.

Hence, No, the average age is not higher than originally believed.

do have an equation or graph or

step-by-step explanation:

(a) common ratio in the given sequence is, 3

(b) push ups will do kendall do on the 20th week

step-by-step explanation:

geometric sequence is a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio(r)

(a)

given the sequence: 6 , 18 , 54 , 162 ,

this sequence is geometric sequence where each term is 3 times the previous term.

therefore,

common ratio(r) = 3.

(b)

a formula for nth term of geometric sequence is given by;

,   where r is the common ratio between the successive terms and is the first term,

to find how many push ups will kendall do on the 20th week.

here. n = 20th term.

in the given sequence first term

then;

simplify:

therefore, push ups will do kendall do on the 20th week