Which statement is not used to prove that δlkm is similar to δnom?

angle k is congruent to itself, due to the reflexive property.

angles mon and mkl are congruent, due to the corresponding angles postulate.

km is a transversal intersecting lk and on.

segments kl and on are parallel.

The answer is Angle K is congruent to itself, due to the reflexive property

Step-by-step explanation:

Angle K doesn't share an angle with both triangles.

Angle K is congruent to itself, due to the reflexive property.

Step-by-step explanation:

I just took the test and that is the correct answer.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

so then what are you asking?

step-by-step explanation: