Gis the sequence of numbers g1, g2, g3…gn such that each term following the first is one more than two times the preceding term. if g2 + g4 = 30! ! , what is the first term in the sequence?

The first term of the sequence is 2.2

Step-by-step explanation:

Let g1 be x,

so that g2 will be

g2 = 1 + 2x

And g3 will be

g3 = 1 + 2(1 +2x)

= 1 + 2 + 4x

=3 + 4x

And g4 will be

g4 = 1 + 2(3+4x)

= 1 + 6 + 8x

= 7 + 8x

If g2 + g4 = 30,

Therefore 1 + 2x + 7 + 8x = 30

8 + 10x = 30

10x = 30 - 8

10x = 22

X= 22/10

X= 2.2

Since x = g1,

Therefore g1 is 2.2

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

idk

step-by-step explanation: