The amounts (in ounces) of juice in eight randomly selected juice bottles are: 15.4 15.8 15.4 15.115.8 15.9 15.8 15.7. construct a 98% confidence interval for the mean amount of juice in all such bottles.

15.33μ15.89

Step-by-step explanation:

given observations

15.4

15.8

15.4

15.1

15.8

15.9

15.8

15.7.

mean(x)=15.6125

Variance (s2): 0.068593750000048

standard deviation(s)=0.2619040854970537

as we dont know the population standard deviation  so we use t-stat

formula

  t,n-1=}" alt="\frac{s}{[tex]\sqrt{n}" />}" />}[/tex]

where

s-sample standard deviation

x-sample mean

μ-population mean

n-sample size

x-t×}" alt="\sqrt{n}" />}" />μ  t×}" alt="\sqrt{n}" />}" />+x

for 98% confidence interval and 7 degrees of freedom

t=2.998

15.33μ15.89 is the 98% confidence interval for mean

beanburito

step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine