Abasketball team sells tickets that cost $10, $20, or, for vip seats, $30. the team has sold 3237 tickets overall. it has sold 145 more $20 tickets than $10 tickets. the total sales are $62030. how many tickets of each kind have been sold?

$10 = 1,546 tickets sold

$20 = 1,691 tickets sold

Step-by-step explanation:

1. Let's re-evaluate and organize our information given by the passage.

Reg. tickets = $10 and $20

VIP seats = $30

Tickets sold (# of all tickets) = 3,237 tickets

Tickets sold OVERALL = 145 more $20 tickets sold than $10 tickets

Money made = $62,030

1. We need to represent x as the amount of the $10 tickets being sold, and y being the amount of $20 tickets being sold, so it'll look similarly like this:

x + y ( x + 145 ) = 3,237

2. Now, let's make estimates on what the # of tickets being for the $10 tickets is (because the # of $10 being sold affects the # of the $20 tickets being sold, and we have to start with this step first to in order find the number of $20 tickets sold).

3.

x = 1,000

y = 1,145

1,000 + 1,145= 2,145

x = 2,000

y = 2,145

2,000 + 2,145 = 4,145

From these 2 estimates, the sales of x is between 1,000 and 2,000.

x = 1,546

y = 1,691

1,546 + 1,691 = 3,237 tickets

do you have the measurements?

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!