A^n=a^1+(n-1)+d how would you solve this?

thats the arithmetic sequence formula!

an = the term u want to find

a1= first term in the list of ordered #s

n= the term position

d= common difference of any pair of consecutive and adjacent #s

a^n=a^1+(n-1)+d is a formula to help find a term in a sequence.

EX: find the 35th term in thr arithmetuc sequence 3,9,15,21

3 THINGS NEEDED:

1. the first term (a1)

2. common difference (d)

3. term position (n)

the first term = a1 = 3

difference = d = 6

term position = n = 35

an = a1 + (n-1)d

a35 = 3 + (35-1)6

= 3 + (34)6

= 3 + 204

a35 = 207

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8