Then for substitution:dx=u du. and integral becomes:
=u-ln(u+1)=
. Now we will change the values of limits: 
=4-ln(5)-2+ln(3)=2+ln(0,6)=2-0.51=1.49
Using the u- substitution u=sqrt(2x), integral form 2-8 dx/ sqrt(2x) + 1 is equivalent to
i'm...
Mathematics, 29.08.2019 14:30, melanie7152
Using the u- substitution u=sqrt(2x), integral form 2-8 dx/ sqrt(2x) + 1 is equivalent to
i'm not quite sure how to solve using u substitution.
!
Answers: 1
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