Dave walked to his friend's house at a rate of 4 mph and returned back biking at a rate of 10 mph. if it took him 18 minutes longer to walk than to bike, what was the total distance of the round trip?

The total distance of the round trip was 4 miles

Step-by-step explanation:

1. Let's check all the information given to answer the question correctly:

Speed of Dave walking to his friend's house = 4 mph

Speed of Dave biking from his friend's house = 10 mph

Time walking is 18 minutes longer than time biking

2. What was the total distance of the round trip?

Time walking = x

Time biking = x - 18

For solving x, we will use the following equation:

4x = 10 * (x - 18)

4x = 10x - 180

-6x = - 180

x = -180/-6 (Dividing by - 6)

x = 30

Dave walked 30 minutes and biked 12 minutes, now we can calculate the total distance, this way:

30 minutes = 0.5 hours and 12 minutes = 0.2 hours

Total distance = 4 * 0.5 + 10 * 0.2

Total distance = 2 + 2

Total distance = 4 miles

The total distance of the round trip can be calculated by creating the system equation as per the given statement.

The total distance is .

Given:

The speed of Dave walked to his friend's house is .

The speed of Dave returned back biking is .

As per the given statement he took 18 min longer to walk.

Let the walking time is , and biking time is .

As per given statement, write the system equation.

Thus, the Dave's walked time is .

Now, Dave's biking time is .

Convert the the minute to hour.

Calculate the total distance covered by Dave.

Learn more about distance and time here:

link

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w